The Big Bang Theory’s Wil Wheaton says it took ‘about 10 years’ to be comfortable playing himself on the show

Wil was an unsung hero of The Big Bang Theory (Picture: CBS)

The Big Bang Theory has become as beloved for its smaller roles as its main characters, with Wil Wheaton being a particular standout as a heightened version of himself.

Nostalgia for the sitcom is at new heights considering its coming to a close with season 12 next month, and actor Will Wheaton has spoken about the journey of getting accustomed to playing himself on the show.

Wheaton has since explained how he separated himself from his character by imagining him as the version of him which didn’t get married, but that became more complicated as the storyline developed.

Speaking to TV Insider about the arc from Sheldon’s nemesis to friend, Wheaton said: ‘When we transition from that Wil Wheaton from being a villain to ally and part of the “friend” group, he started to become more like who I am.

Wil Wheaton and Jim Parsons as Sheldon Cooper (Picture: Sonja Flemming/CBS via Getty Images)

‘That was an adjustment. First, I had to adjust to being a villain to, basically, being myself. It took me about ten years, but I could finally make that separation and be comfortable about being a heightened version of myself.’

Wheaton is very thankful for the show generally, adding: ‘It has meant so much. It’s been such an incredible gift to work with these magnificent actors, this phenomenal writing staff, and just the most amazing and professional crew with which I’ve ever worked.

‘We could spend our entire careers hoping to have one experience like I have working on TBBT.’

Co-star Kaley Cuoco, who plays Penny, recently posted a picture teasing the next episode which is promising all the emotions.

The Big Bang Theory airs Thursdays on CBS and E4 in the UK.

MORE: Kaley Cuoco shares behind-the-scenes photo of new The Big Bang Theory final season episode: ‘Cue the tears’

MORE: Why are there so many scheduling gaps between The Big Bang Theory’s new episodes?


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